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=4T^2
We move all terms to the left:
-(4T^2)=0
a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$T=\frac{-b}{2a}=\frac{0}{-8}=0$
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